- Thread starter
- #1

#### wishmaster

##### Active member

- Oct 11, 2013

- 211

x

^{4}-2x

^{3}-25x

^{2}+50x

I have done it so,but im not sure if this is ok:

x(x

^{3}-2x

^{2}-25x+50)

= x(x

^{2}(x-2)-25(x+2)

= x(x

^{2}-25)(x-2)

=x(x-5)(x+5)(x-2)

Now i see that root/zeroes are +5,-5 and 2. I know that this polynomial has another zero that is 0,but how do i know that? Because x is in the front? Or did i make a mistake and should such problems deal another way? Thank you for all replies!