Find the Max Compression of a 2.80kg Block

[physics333]

A block having a mass of 2.80 kg is given an initial velocity of 1.2m/s when it collides with a spring. The constant force of friction acts between the block and the surface with (mu sub k=0.5) and the force constant of the spring is k=100N/m. What is the maximum compression?

I've been stuck on the problem for a while.
Workfriction + KEi + PEi = KE + PE

KEi =2.02J
fk =13.72
KE=0
PEi =0

therefore (13.72 N + 2.02 J)/ 50N/m = x^2

Is this equation right? If so, how do I find x?
I tried to work it but I can't figure out how to add Newtons and joules divided by N/m and end up with x in meters...

Please help

 

[StephenPrivitera]

1N=1kgm/s² ---- remember F=ma?
1J=1kgm²/s² ----- remember W=Fx?

 

[physics333]

I still need more information...I'm not as smart as some as you. Someone get me started and I can figure it out...
Thanks

 

[NateTG]

Originally posted by physics333

therefore (13.72 N + 2.02 J)/ 50N/m = x^2

There should be massive alarms going off when you get N+J in a physics problems.

If you put your equation together right, this should be easy:

KE_i=Work_friction+PE_spring
or
1/2mv₀²=f_frictionx+1/2kx²

Just remember the quadratic formula.