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Pi Day

grgrsanjay

New member
Jan 28, 2012
21
Woo Hoo

Pi Day is observed on March 14 because of the date's representation as 3/14 in month/day date format. This representation adheres to the commonly used approximation of 3.14 for π.

The fractional approximation of π,227, resembles the date July 22 in the day/month format, where it is written 22/7. Pi Approximation Day is therefore celebrated on July 22.

See this http://en.wikipedia.org/wiki/File:Pi_pie2.jpg

Great for celebrating this day(Handshake)
 

Jameson

Administrator
Staff member
Jan 26, 2012
4,042
Was thinking about this earlier. Happy Pi Day everyone!! (Party)
 

grgrsanjay

New member
Jan 28, 2012
21
Not to forget

Today is Albert Einstein's Birthday
 

SuperSonic4

Well-known member
MHB Math Helper
Mar 1, 2012
249
Guess I'll be waiting until July then (Giggle). Then again the fact it's Wednesday is a good enough reason to eat pi [sic]
 

Sherlock

Member
Jan 28, 2012
59

mvCristi

New member
Feb 5, 2012
1
Happy "pi day" to everyone.

I hope we will all get to celebrate the entire month of February, '71 together. ;) :p
 

sbhatnagar

Active member
Jan 27, 2012
95
I'll send you a postcard with $\int_{0}^{1}\frac{x^4(1-x)^4}{1+x^2}\;{dx}$ on it. (Devil)
Surprisingly, $\displaystyle \int_{0}^{1}\frac{x^4(1-x)^4}{1+x^2}\;{dx}=\frac{22}{7}-\pi$.
 

Sherlock

Member
Jan 28, 2012
59
Surprisingly, $\displaystyle \int_{0}^{1}\frac{x^4(1-x)^4}{1+x^2}\;{dx}=\frac{22}{7}-\pi$.
Yes, and since the integrand is positive, it proves that in fact $\pi > 22/7.$ (Rock)

That was the point of the joke (for more on the integral, see here).
 

sbhatnagar

Active member
Jan 27, 2012
95