- Thread starter
- #1

Hello Everybody,

A trapper walks a 6.2 km straight-line distance from the cabin to the lake, beginning to the lake has an angle of +45 degrees. Determine the east and north components of her dispacement vector.

Work:

E component: $6.2\times\cos\left({45^{\circ}}\right)$ = 4.38

N Component:$6.2\times\sin\left({45^{\circ}}\right)$=4.38

I have troubles to next question:

How many more kilometers would the trapper have to walk if she walked along the component displacements?

A trapper walks a 6.2 km straight-line distance from the cabin to the lake, beginning to the lake has an angle of +45 degrees. Determine the east and north components of her dispacement vector.

Work:

E component: $6.2\times\cos\left({45^{\circ}}\right)$ = 4.38

N Component:$6.2\times\sin\left({45^{\circ}}\right)$=4.38

I have troubles to next question:

How many more kilometers would the trapper have to walk if she walked along the component displacements?

Last edited: