- #1
JSGhost
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Homework Statement
A heat pump has a coefficient of performance of 3.70 and operates with a power consumption of 6.91 103 W.
(a) How much energy does it deliver into a home during 1 h of continuous operation?
9.2x10^7 J
(b) How much energy does it extract from the outside air?
? J
Homework Equations
COP(coefficient of performance) = |Q_h|/W
P = W/t
W = P*t
e = W_eng/|Q_h| = (|Q_h|-|Q_c|)/|Q_h| = 1 - |Q_c|/|Q_h|
The Attempt at a Solution
(a) I got this part correct.
COP = |Q_h|/W
P = W/t
W = P*t
|Q_h| = COP*W = COP * P*t = 3.70(6.91x10^3 J/s)(3600s) = 9.2x10^7 J
(b) I need help on part (b). I can't get the correct answer.
I tried using e = 1 - |Q_c|/|Q_h|
|Q_c| = |Q_h|(e-1) = 9.2x10^7 J (3.70-1)
but that answer doesn't work.