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- Thread starter copperfox
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- Mar 5, 2012

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Hi copperfox! Welcome to MHB!here's the question:

a = b/e

b = 1 kg m^{-1}

e = 1 kg m^{-2}

what is a? including units

I assume it's to do with cancelling out the units when you divide but I really don't know what the answer is

Indeed. It's about canceling out the units.

It works like this:

$$a=\frac be

= \frac{1\cdot\text{kg}\cdot\text{m}^{-1}}{1\cdot\text{kg}\cdot\text{m}^{-2}}

= \frac{1\cdot\cancel{\text{kg}}\cdot\text{m}^{-1}}{1\cdot\cancel{\text{kg}}\cdot\text{m}^{-2}} \cdot\frac{\text{m}^2}{\text{m}^2}

= \frac{1\cdot\text{m}^{1}}{1\cdot\text{m}^{0}}

= \frac{1\cdot\text{m}}{1\cdot1}

= 1\,\text{m}

$$

- Jan 30, 2018

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