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#### DeusAbscondus

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- Jun 30, 2012

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but I can't seem to get the next part loaded within my set upload limit.

Any help would be appreciated.

D'Abs

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- Jun 30, 2012

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but I can't seem to get the next part loaded within my set upload limit.

Any help would be appreciated.

D'Abs

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- Jun 30, 2012

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But would that not be equivalent to multiplying the entire volume of the block by the volume of the cut out 3d flower?I think you need to write the volumeVin cm^{3}as:

$\displaystyle V=15\cdot55^2-4\cdot100\cdot15\int_0^{\frac{1}{4}}\frac{\sqrt{x}}{2}-4x^2\,dx$

Do you see why?

$$1. 15\cdot 55^2 \text {is the volume of the uncut prism and the integrand is the curve }y=\frac{\sqrt{x}}{2}-y=4x^2$$

I will have to take the current screenshot down and put the next one up; awkward, but space won't allow for both at the same time.

thanks heaps for helping,

D'abs

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- Jun 30, 2012

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I am taking the volume of the prism and subtracting from it the volume of the leaf design which is cut through it.

Ah, that is my problem: I can 't see why one may not derive the volume of design without reference to the volume of the block from which it is "hewn", except that datum of depth: in this case 15cm.

The references to width and length, to the volume of entire block, seem to be entirely beside the point:

surely all you need is:

- the area of one leaf;

- knowledge that each leaf is identical AND that the front and back of the design are identical; and finally,

- depth of block

then it is simply:

$$4\cdot 15cm \int^{1/4}_0 [f(x)-g(x)] dx $$

Isn't it?

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You could, but it would be much more difficult I think.Ah, that is my problem: I can 't see why one may not derive the volume of design without reference to the volume of the block from which it is "hewn".

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- Jun 30, 2012

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My notes say:You could, but it would be much more difficult I think.

"The volume of concrete in the block:

= face area x depth

= 0.03288

Therefore, the concrete required is about 0.03288 m^3 or 33000cm^3"

This is what i mean: "face area x depth" should mean, on the face of it, the result one obtains from integrating the difference between the given functions

Bringing in the volume of the entire square just confuses me.

Still confused.

Thanks anyway,

D'abs

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