- #1
erok81
- 464
- 0
This is more of a general question than a homework problem.
We haven't gotten too far into e&m so maybe there is a different use for this later on that I just haven't seen yet. Even skipping 7-8 chapters ahead, it is still used in the same way.
What is the point of using [tex]\frac{1}{4\pi\epsilon_{0}}[/tex] in place of the usual value for K? The only detail my textbook has gone into it is "It turns out we can make many future equations easier if we rewrite Coulomb's law in a somewhat more complicated way."
Two chapters later we are still writing [tex]\frac{1}{4\pi\epsilon_{0}}[/tex] in the equations, but using the value for K when the final answer is calculated.
So if K = [tex]\frac{1}{4\pi\epsilon_{0}}[/tex], why not just use K?
I'm not arguing why to use K instead of the more complicated version, but more to understand why and when it will come into play later.
We haven't gotten too far into e&m so maybe there is a different use for this later on that I just haven't seen yet. Even skipping 7-8 chapters ahead, it is still used in the same way.
What is the point of using [tex]\frac{1}{4\pi\epsilon_{0}}[/tex] in place of the usual value for K? The only detail my textbook has gone into it is "It turns out we can make many future equations easier if we rewrite Coulomb's law in a somewhat more complicated way."
Two chapters later we are still writing [tex]\frac{1}{4\pi\epsilon_{0}}[/tex] in the equations, but using the value for K when the final answer is calculated.
So if K = [tex]\frac{1}{4\pi\epsilon_{0}}[/tex], why not just use K?
I'm not arguing why to use K instead of the more complicated version, but more to understand why and when it will come into play later.