Period of a Simple Pendulum in a Moving Truck

In summary, the conversation is discussing the application of the simple pendulum formula to a pendulum placed in a truck that is accelerating horizontally. The individual is unsure of how to account for the horizontal acceleration and whether the truck's frame is an inertial frame. They also discuss the derivation of the pendulum oscillation equations and how to account for small oscillations about the equilibrium position.
  • #1
lydster
7
0
A simple pendulum is 8.00 meters long.(a) What is the period of simple harmonic motion for the pendulum if it is place in a truck that is accelerating horizontally at 2.00 m/s^2There were 2 other questions with accelerating upward and downward in an elevator, and those numbers I either added or subtracted to the gravational acceleration. And that gave me my right answers, but I don't know what to do with the horizontal acceleration.
 
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  • #2
Well don't just add or subtract. How do the directions of the accelerations affect the pendulum mass? What determines the motion of a pendulum mass?
 
  • #3
berkeman said:
Well don't just add or subtract. How do the directions of the accelerations affect the pendulum mass? What determines the motion of a pendulum mass?
I'm using the equation T= 2 pi square root of (L/G) and I don't know what I'd do with the horizontal acceleration. Because for vertical accleration I just added to G like 9.8 + 2.00 m/s^2 or 9.8 - 2.00 m/s^2 and that was correct for my other two parts of the problem. The mass is not supposed to have anything to do with the problem I guess.
 
  • #4
Did your instructors (or the textbook) give you the derivation of the "canned" pendulum oscillation equations? This question may be kind of hard to address without the basic equations...
 
  • #5
berkeman said:
Did your instructors (or the textbook) give you the derivation of the "canned" pendulum oscillation equations? This question may be kind of hard to address without the basic equations...
No, just whatever I posted above is what he gave us. What do you mean by "canned"?
 
  • #6
lydster said:
No, just whatever I posted above is what he gave us. What do you mean by "canned"?
Often in physics classes, you will be given a formula to apply. But when you are given a different setup or initial conditions or situation, the canned formula will not apply. That is when you need to go back to the original derivation to figure out the answer for the new problem statement.

Like, in SHM instruction, you will end up with formulas for omega-0, damping factor, Q, etc. But what happens when there is lateral acceleration or viscous damping added in? In that case you need to go back to the original equations that you/others used to derive the expected behavior, and be sure that the new effects are part of the derivation.

This comes up a lot in my EE work. When you push the edges of datcomm stuff, with unique and varied comm channels, you need to be sure that you're still working correctly in your simulations. Like when you change your carrier frequency, several different things can happen to many of your variables in your simulations (and the resulting real world effects).
 
  • #7
lydster:
Try and formulate the equations of motion in the rest frame of the truck.
1. Is this an inertial frame?
2. If the pendulum is at rest relative to the truck, is the pendulum hanging straight down?

3. We generally derive the oscillatory motion of a pendulum by assuming small oscillations ABOUT THE EQUILIBRIUM POSITION OF THE PENDULUM!
In light of your answer to 2., how should you tweak your equations of motion to account for such small oscillations?
 
  • #8
I don't know if it's an internal frame. I think we're assuming it might be? Yes the pendulum is hanging straight down, because we're assuming again that it starts from rest.

I'm just not sure where to go from there.
 
  • #9
lydster said:
I don't know if it's an internal frame.
I asked you if the REST frame of the truck was an INERTIAL frame.
Do you know what those terms mean?
Yes the pendulum is hanging straight down, because we're assuming again that it starts from rest.

Wherever is that assumption stated?

Besides, I asked you about the pendulum's position when it was at rest with respect to the truck.
 

Related to Period of a Simple Pendulum in a Moving Truck

1. What is a simple pendulum?

A simple pendulum is a mass (usually a bob or weight) attached to a fixed point by a string or rod. It is a classic example of a harmonic oscillator and exhibits regular periodic motion.

2. How does a simple pendulum work in a moving truck?

A simple pendulum in a moving truck will still exhibit regular periodic motion, but its period will be affected by the truck's motion. As the truck accelerates or decelerates, the pendulum will experience an additional force, causing its period to change.

3. What factors affect the period of a simple pendulum in a moving truck?

The period of a simple pendulum in a moving truck is affected by the truck's acceleration, the length of the pendulum, and the force of gravity. Additionally, air resistance and the angle of the pendulum's swing may also have an impact.

4. How does the period of a simple pendulum in a moving truck change with the truck's speed?

The period of a simple pendulum in a moving truck will decrease as the truck's speed increases. This is because the pendulum's motion is affected by the truck's acceleration, and the faster the truck moves, the more force is applied to the pendulum, causing it to swing faster and thus decreasing its period.

5. How can the period of a simple pendulum in a moving truck be calculated?

The period of a simple pendulum in a moving truck can be calculated using the equation T = 2π√(L/g), where T is the period, L is the length of the pendulum, and g is the acceleration due to gravity. However, this equation may need to be adjusted to account for the truck's motion and any other factors that may affect the pendulum's period.

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