Help Struggling Student w/ Glancing Collisions Qs

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In summary, the bullet initially travels at a speed of 8.00g before crashing into the block. The block then falls 2.00m to the ground after the collision and loses energy in the process, resulting in a speed of 5.80g.
  • #1
ScoutFCM
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I'm stuck, for the past 30 minutes. Anyone care to give a struggling student a hand? Any help would be appreciated due to that fact that I don't understand the material. I have notes, yet I have one of those teachers who talk, but don't teach. I don't know. Thanks to anyone who can help me out.

1.) An 8.00g bullet is fired into a 250g block that is initially at rest at the edge of a table of height 1.00m. The bullet remains in the block and after the impact the block lands 2.00m from the bottom of the table. Determine the initial speed of the bullet.

2.) A 1200kg car traveling initially with a speed of 25m/s in an eaterly direction crashes into the rear end of a 9000kg truck moving in the same direction at 20m/s. The veolcity of the car right after the collision is 18m/s to the east. What is the velocity of the truck right after the collision? How much mechanical enegry is lost in the collision? Account for this loss in energy.

3.) Two automobiles of equal mass approach an intesection. One vehicle is traveling with velocity 13m/s toward the east and the other is traveling north with speed V2i. Neither driver sees each the other. The vehicles collide in the intersection and stick together, leaving parallel ski marks at an angle of 55 degrees north of east. The speed limit for both roads is 35mi/hr and the driver of the northward-moving vehicle claims he was within the speed limit when the collision occurred. Is he telling the truth?
 
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  • #2
1. Assume the table is frictionless so that the velocity it gets after the collision is the same as the velocity it has as it leaves the table. The first thing you should do is find what this velocity is: you know how far away from the table it landed and how high it started off, so just use kinematics to find what the initial (x) velocity must have been. Then use the conservation of momentum. This is an inelastic collision and the block starts at rest, so you can simply write mv = (m+M)V, where m is the bullet mass, M is the block mass, v is the unknown bullet velocity, and V is the velocity you just found from kinematics.

2. Use the conservation of momentum. If you write some work out for this one, I (or someone else) will try to give more specific help. You can calculate the kinetic energy before and after the collision to find how much was lost. Where do you think the energy may have been lost to?

3. Again, conservation of momentum. Remember that momentum is a vector quantity, so that when you have a 2-dimensional problem like this one, you will get 2 equations (assuming you resolve things into components). You know the orientation of the post-collision momentum along with the fact that the vehicles stick together (effectively become one mass) after the collision. It will be easier on both of us if you write out your initial thoughts and equations on this problem. Once you have solved for the unknown initial velocity of the north-bound driver, you can convert it to the proper units and determine if he was above or below the speed limit.
 
  • #3
Geez, you should be my teacher. Your explanation in 6 lines taught me more than my teacher did in 3 class periods. Haha. Off to doing my work...
 

1. What are glancing collisions?

Glancing collisions are a type of collision that occurs between objects where the impact is at an angle rather than head on. In these collisions, the momentum and kinetic energy of the objects are not conserved.

2. How do glancing collisions differ from head-on collisions?

In head-on collisions, the objects involved have a direct and equal impact, resulting in the conservation of momentum and kinetic energy. In glancing collisions, the objects have an oblique impact, resulting in the loss of energy and momentum.

3. How can I help a struggling student with glancing collisions questions?

One way to help a struggling student with glancing collisions questions is to go over the fundamental concepts of momentum, kinetic energy, and conservation laws. It may also be helpful to provide visual aids or real-life examples to better illustrate the concept.

4. What are some common misconceptions about glancing collisions?

One common misconception about glancing collisions is that the objects involved always have the same amount of force applied to them. In reality, the force applied to each object depends on the angle of impact and the mass of the objects. Another misconception is that kinetic energy is always conserved in glancing collisions, which is not true.

5. How can I apply the concept of glancing collisions in real life?

The concept of glancing collisions can be applied in various fields, such as sports, engineering, and transportation. For example, understanding glancing collisions can help in designing safer cars with crumple zones to absorb energy during collisions. It can also be used to analyze the trajectory of a football after it bounces off the goalpost or the angle of a hockey puck after being hit by a stick.

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