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- #1

$$

\mathbf{r}(t) = \hat{\mathbf{x}}R\cos(\omega t) + \hat{\mathbf{y}}R\sin(\omega t)

$$

The particle moves in a circle so I want to show that the position is given by the above.

I know at $t = 0$ the particle is on the x-axis.

Therefore, we know that at t = 0, $(R,0)$.

Obviously it has to be that but I guess there is a way to show this basically.