- Thread starter
- #1

- Thread starter lucad93
- Start date

- Thread starter
- #1

Put the partial fraction back over a common denominator:

$$

V(z)=\frac{A}{z-3}+\frac{B}{(z-1)^2}+\frac{C}{z-1}=\frac{A(z-1)^2+[B+C(z-1)](z-3)}{(z-3)(z-1)^2}

$$

The coefficient of $z^2$ in the numerator is $A+C=1 $

.

- Dec 11, 2019

- 9

Now,plugging any number into z,say 0;

-4/3 = -1/3 -2 -C .Then,

C=-1