Partial Derivative of a formula based on the height of a cylinder

In summary, the function should use (r,z,t) variables and the domain is (0,H). Since U is not dependent on angle, theta can be ignored in the expression for Laplacian in cylindrical coordinates. This is because the boundary and initial conditions also do not depend on theta, making the problem symmetric under rotations around the z-axis. Therefore, a separation ansatz can be used, as the boundary and initial conditions can also be separated into a product of r and z.
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Homework Statement
Consider a cylinder of radius a and height H. The base of the cylinder is at z=0 and the top is at z=H. Find a function which satisfies ∂U/∂t = k(nabla)^2U in the domain and stated boundary conditions and initial conditions.
Relevant Equations
* ∂U/∂t = k∇^2U
* Boundary condition: U=0 on the surface of the cylinder at all times.
* Initial condition: U within the domain = α(r)β(z) at time t=0 where α(r)=e^-r
The function should use (r,z,t) variables
The domain is (0,H)

Since U is not dependent on angle, then theta can be ignored in the expression for Laplacian in cylindrical coordinates(?)
 
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Yes, because also the boundary and initial conditions do not depend on ##\theta##, the problem is symmetric under rotations around the ##z##-axis. Then I'd try a separation ansatz since also the boundary and initial conditions separate into a product of ##r## and ##z##.

BTW: It would help very much, if you'd use the LaTeX features of the Forum software (MathJaX), because it makes the formulae much better readable:

https://www.physicsforums.com/help/latexhelp/
 
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Related to Partial Derivative of a formula based on the height of a cylinder

What is a partial derivative?

A partial derivative is a mathematical concept that measures the rate of change of a function with respect to one of its input variables, holding all other variables constant.

How is the partial derivative of a formula based on the height of a cylinder calculated?

The partial derivative of a formula based on the height of a cylinder is calculated by taking the derivative of the formula with respect to the height variable, while treating all other variables as constants.

Why is the partial derivative of a formula based on the height of a cylinder important?

The partial derivative of a formula based on the height of a cylinder is important because it helps us understand how the volume of the cylinder changes as its height changes. This information is crucial in various fields such as engineering, physics, and economics.

What are the key applications of partial derivatives in relation to cylinder height?

Some key applications of partial derivatives in relation to cylinder height include finding the maximum or minimum volume of a cylinder, optimizing the volume of a cylinder subject to certain constraints, and determining the sensitivity of the volume to changes in height.

Can the concept of partial derivatives be extended to other shapes besides cylinders?

Yes, the concept of partial derivatives can be extended to other shapes besides cylinders. It can be applied to any multi-variable function, where one variable is of interest and the rest are treated as constants.

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