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Partial DE-separation of variables

emily600

New member
Oct 29, 2013
2
Hi I'm having a bit of trouble with this question:

Use separation of variables to find all the possible separable solutions to the partial DE equation for u(x,y) given by
yux - 3x2 uy = 0
.


I try u= X(x) Y(y)

ux = X'(x) Y(y)

uy = X(x) Y'
(y)


which gives y(X' Y)-3x2(X Y')

then I divide by (XY) and rearrange it into y[X'/X] = 3x2 [Y'/Y]

which is equal to the separationconstant K (I think)

y[X'/X] = 3x2 [Y'/Y] = K


and from here I get a bit lost. I try a positive constant, so I get two equations.

yX'/X = + K rearranged into {X'= XK/y}

3x2Y/Y = + K rearranged into {Y'= YK/3x2 }


and then I try a negative constant with more or less the same equations resulting, but I'm not sure what to do with them?

Is this how you find all the possible solutions of the pde (trying both a positive and a negative constant)?

I'm told I can check the solution by substitution but I'm not sure how. Any help would be really appreciated.

Thanks:confused::confused:.
 

Opalg

MHB Oldtimer
Staff member
Feb 7, 2012
2,725
Hi I'm having a bit of trouble with this question:

Use separation of variables to find all the possible separable solutions to the partial DE equation for u(x,y) given by
yux - 3x2 uy = 0
.


I try u= X(x) Y(y)

ux = X'(x) Y(y)

uy = X(x) Y'
(y)


which gives y(X' Y)-3x2(X Y')

then I divide by (XY) and rearrange it into y[X'/X] = 3x2 [Y'/Y]

which is equal to the separationconstant K (I think)

y[X'/X] = 3x2 [Y'/Y] = K
You would do better to rearrange it as $\mathbf{\dfrac{X'}{x^2X}} = \mathbf{\dfrac{3Y'}{yY}}$. The left side is then purely a function of $\mathbf{x}$ and the right side is then purely a function of $\mathbf{y}.$ You are then justified in putting both sides equal to a separation constant, and you have two separate ODEs for $\mathbf{x}$ and $\mathbf{y}$.
 

emily600

New member
Oct 29, 2013
2
Thanks that simplified things a little. For the positive constant I solved the 2 ODE's as:

ode.png

And then put them together. If I do the same for a negative constant would that cover the possible solutions (assuming I can rearrange and solve them properly)?

Thanks:D