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Trigonometry Part of a Trig problem

Ineedhelppp

New member
Nov 16, 2013
4
Couldn't figure out why. Where 0.27 deg =3pi/2000. Now the only way I could figure this out is 270 deg = 3pi/2. multiply by 1000 to get the 270 and the 2000, but gives 3000pi/2000? Anyone tell me where this came? Thanks
 
Last edited:

Klaas van Aarsen

MHB Seeker
Staff member
Mar 5, 2012
8,780
So this is a small part thats given in a problem which I don't know where came from. Where 0.27 deg =3pi/2000. Now the only way I could figure this out is 270 deg = 3pi/2. multiply by 1000 to get the 270 and the 2000, but is it still 3pi/2000 and not 3000pi/2000? Anyone tell me where this came? Thanks
Welcome to MHB, Ineedhelppp! :)

I'm not entirely sure where you are stuck.


You have:
$$270^\circ = \frac{3\pi}{2}$$
Multiply both sides by 1/1000:
$$270^\circ \cdot \frac{1}{1000} = \frac{3\pi}{2} \cdot \frac{1}{1000}$$
Apply the rules how to multiply fractions:
$$0.27^\circ = \frac{3\pi \cdot 1}{2 \cdot 1000}$$
Simplify:
$$0.27^\circ = \frac{3\pi}{2000}$$
 

Ineedhelppp

New member
Nov 16, 2013
4
Thank you so much. Once you go days studying, you start to lose focus on simple things. Thanks again.