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- #1

#### Dnichol016

##### New member

- May 11, 2020

- 4

2[1/4 + 4(36 divided by 12)]

its 2 to the 3rd power. How do you solve this?

its 2 to the 3rd power. How do you solve this?

- Thread starter Dnichol016
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- Thread starter
- #1

- May 11, 2020

- 4

2[1/4 + 4(36 divided by 12)]

its 2 to the 3rd power. How do you solve this?

its 2 to the 3rd power. How do you solve this?

- Admin
- #2

- Jan 29, 2012

- 1,151

The "deepest" parentheses are "(36 divided by 12)" which is 3 so2[1/4 + 4(36 divided by 12)]

its 2 to the 3rd power. How do you solve this?

that reduces to "2[1/4+ 4(3)]= 2[1/4+ 12]. Now 1/4+ 12= 1/4+ 48/4= 49/4

so we can reduce further to 2[49/4]= 49/2. That is NOT 2^3= 8.

It is possible that you intended the "4+ 4(36 divided by 23)" to all be in the denominator, not just the 4. That would require one more set of brackets:

2[1/{4+ 4(36 divided by 23)}]= 2[1/{4+ 4(3)}]= 2[1/(4+ 12)]= 2[1/16]= 2/16= 1/8.

But 1/8 is still not 8!

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- #4

- May 11, 2020

- 4

Yes it’s in my grandsons homeworkHello, and welcome to MHB!

As written, the expression evaluates to:

\(\displaystyle \frac{49}{2}\)

Are you certain you have copied it correctly?

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- #5

- May 11, 2020

- 4

- Admin
- #6

\(\displaystyle 2^3\left[\frac{1}{4}+4(36\div12)\right]\)

Do the division within the innermost brackets:

\(\displaystyle 2^3\left[\frac{1}{4}+4(3)\right]\)

Do the indicated multiplication within the brackets:

\(\displaystyle 2^3\left[\frac{1}{4}+12\right]\)

Do the indicated addition within the brackets:

\(\displaystyle 2^3\left[\frac{49}{4}\right]\)

Rewrite \(2^3\) as \(8\):

\(\displaystyle 8\left[\frac{49}{4}\right]\)

Do the indicated multiplication:

\(\displaystyle 8\left[\frac{49}{4}\right]=2\cdot49=98\)

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- #7

- May 11, 2020

- 4

Thank yo so much