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Trigonometry Parallelogram with diagonals. Need to find the area (S).

STS

New member
Mar 19, 2019
5
diagonal 1=20cm.
diagonal 2=37cm.
AB=25.5cm

S (AMC)= 306cm.
S (ABCD)=?
 

Wilmer

In Memoriam
Mar 19, 2012
376
Ottawa Ontario Canada

Country Boy

Well-known member
MHB Math Helper
Jan 30, 2018
343
diagonal 1=20cm.
diagonal 2=37cm.
AB=25.5cm
Okay, that makes sense.

S (AMC)= 306cm.
S (ABCD)=?
What?? What is "S( )"? What is "M"? Is it another point? The midpoint where the two diagonals intercept?
 

STS

New member
Mar 19, 2019
5
Last edited:

STS

New member
Mar 19, 2019
5
Okay, that makes sense.


What?? What is "S( )"? What is "M"? Is it another point? The midpoint where the two diagonals intercept?
S is the area. You move one of the diaganals to the side, then that forms a triangle. Then with Heron's formula you figure out the area of the triangle that has formed (AMC). That is suppose to help you figure out the area of the parallelogram using another formula, but I couldn't figure it out.
 

Wilmer

In Memoriam
Mar 19, 2012
376
Ottawa Ontario Canada
S is the area. You move one of the diaganals to the side, then that forms a triangle. Then with Heron's formula you figure out the area of the triangle that has formed (AMC). That is suppose to help you figure out the area of the parallelogram using another formula, but I couldn't figure it out.
OK; then WHY did you post only this:
..............................
diagonal 1=20cm.
diagonal 2=37cm.
AB=25.5cm

S (AMC)= 306cm.
S (ABCD)=?
..............................

You're given the 2 diagonals plus 1 side.
That's plenty of info to calculate the area.
S(AMC) = 306 not required...