Apprentice123 said:A parallel plate capacitor is formed using a material whose dielectric constant is 3,00 and whose dielectric strength is 2x10^{8} V/m. The capacitance is 0,25x10^{-6}F and the capacitor must withstand a potential difference maximum of 4000V. Find the minimum area of the plates of the capacitor
I have
C = (E. * A * k)/d
How to calculate d ?
LowlyPion said:How will the dielectric strength constrain the distance separation?
Then solve for A.
Apprentice123 said:the dielectric strength (2x10^8 V/m) is the separation of the plates?
LowlyPion said:No. That's a property of the material if it was 1 meter thick.
How thick does it need to be to yield a 4000 V rating?
Apprentice123 said:V = (q*d)/(E.*A*k)
It is related to d and A again
LowlyPion said:Like I said, find d.
For this problem minimum d is the thickness required to provide a 4000 V separation between the plates. That means that with a dielectric strength of 2*108 you need a thickness of 4000/2*108 2*10-5 m.
Then apply that to Area calculation.
Edit: I see you have in your next post. So yes. That looks like the right way to do it.
A parallel plate capacitor is a type of electrical device that is used to store electrical charge. It consists of two parallel conducting plates separated by an insulating material, known as the dielectric. When a voltage is applied to the plates, a potential difference is created, causing one plate to become positively charged and the other to become negatively charged.
The capacitance of a parallel plate capacitor can be calculated using the formula C = εA/d, where C is the capacitance, ε is the permittivity of the dielectric material, A is the area of the plates, and d is the distance between the plates.
The dielectric material in a parallel plate capacitor serves as an insulator between the two plates, preventing them from coming into direct contact. It also increases the capacitance of the capacitor by reducing the electric field between the plates.
The capacitance of a parallel plate capacitor is inversely proportional to the distance between the plates. This means that as the distance between the plates increases, the capacitance decreases, and vice versa.
Parallel plate capacitors have various applications in everyday life, including in electronic devices such as computers, radios, and televisions. They are also used in power factor correction, electronic filters, and energy storage systems. Additionally, parallel plate capacitors are used in the automotive industry for ignition systems and in medical devices such as defibrillators.