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#### Alexmahone

##### Active member

- Jan 26, 2012

- 268

Find all prime numbers p for which p!+p is a perfect square.

p!+p=p[(p-1)!+1]

By Wilson's theorem, (p-1)!+1 is divisible by p. Now I'm stuck.

**: 2!+2 and 3!+3 are perfect squares.**__My thoughts__p!+p=p[(p-1)!+1]

By Wilson's theorem, (p-1)!+1 is divisible by p. Now I'm stuck.

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