- #1
Firepanda
- 430
- 0
I don't have any example of this in my notes:
I have the permutation p1 = (1 5)(2 4 6 3)
and the permutation p2 = (1 3 7 4)(2)(5 8 6)
and I have to find p2 * p1
i THINK you take it in the form p1 then p2, like:
(1 5)(2 4 6 3)(1 3 7 4)(2)(5 8 6) = ...
But them I'm stuck.
I tried googling some info, but it was all too vague.
I had an attempt which ended up in:
1 -> 5 in p1, then 5 -> 8 in p2 so 1 -> 8
etc
so p2*p1 = (1 8)(2 1 8)(3 2 1 8)(4 5 3 2 1 8)(6 7)
= (4 5 3 2 1 8)(6 7)
Looks right? :P
I have the permutation p1 = (1 5)(2 4 6 3)
and the permutation p2 = (1 3 7 4)(2)(5 8 6)
and I have to find p2 * p1
i THINK you take it in the form p1 then p2, like:
(1 5)(2 4 6 3)(1 3 7 4)(2)(5 8 6) = ...
But them I'm stuck.
I tried googling some info, but it was all too vague.
I had an attempt which ended up in:
1 -> 5 in p1, then 5 -> 8 in p2 so 1 -> 8
etc
so p2*p1 = (1 8)(2 1 8)(3 2 1 8)(4 5 3 2 1 8)(6 7)
= (4 5 3 2 1 8)(6 7)
Looks right? :P