- #1
Breo
- 177
- 0
Hello,
I am learning Feynman diagrams and I still do not understad quite well the symmetry factor idea. The equation is:
$$ \frac{1}{O(G)} = \frac{M}{n!(4!)^n} $$
I was trying the next example:
If I am not wrong it is O(G) = 10 taking care of the asymmetry of each pair of internal lines connecting vertices.
I am learning Feynman diagrams and I still do not understad quite well the symmetry factor idea. The equation is:
$$ \frac{1}{O(G)} = \frac{M}{n!(4!)^n} $$
I was trying the next example:
If I am not wrong it is O(G) = 10 taking care of the asymmetry of each pair of internal lines connecting vertices.