- Thread starter
- #1

Hii Every one,

In one paper I read that, \(\displaystyle {\displaystyle \sum_{j\geq1}\left(\frac{c*m*logm}{2^{\left(\frac{j-1}{2}\right)}}\right)}^{j}<=m^{o(logm)}

\) with the explanation "Since the sum is of the same order as its largest term".

c>0, m>=2. m is an integer.

Can anyone pls explain?

Regards,

Bincy

In one paper I read that, \(\displaystyle {\displaystyle \sum_{j\geq1}\left(\frac{c*m*logm}{2^{\left(\frac{j-1}{2}\right)}}\right)}^{j}<=m^{o(logm)}

\) with the explanation "Since the sum is of the same order as its largest term".

c>0, m>=2. m is an integer.

Can anyone pls explain?

Regards,

Bincy

Last edited: