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Number Theory numbers of divisors

jacks

Well-known member
Apr 5, 2012
226
(1) The number of divisers of the form $2^2.3^3.5^3.7^5$ which are is in the form of $4n+1$ where $n\in\mathbb{N}$

(2) Calculate Total no. of positive Divisers of $7!$ which are is in the form of $3t+1\;,$ where $t\in \mathbb{N}$
 

Klaas van Aarsen

MHB Seeker
Staff member
Mar 5, 2012
8,791
(1) The number of divisers of the form $2^2.3^3.5^3.7^5$ which are is in the form of $4n+1$ where $n\in\mathbb{N}$

(2) Calculate Total no. of positive Divisers of $7!$ which are is in the form of $3t+1\;,$ where $t\in \mathbb{N}$
Hi jacks! :)

Where are you stuck?
Did you try anything?