- #1
Swigs
- 8
- 0
The problem was pretty simple i thought, but according to the book i get the wrong answer. I think i might be approching the problem wrong.
"In the drawing, the weight of the block on the table(block1) is 422N and that of the hanging block(block2) is 185N. Ignoring all frictional effects and assuming the pulley to be massless, find (a) the acceleration of the two blocks and (b) the tension in the cord."
o-----------Block1
I
I
I
Block2
(excuse my poor excuse for trying to draw with letters)
What I did was since we know that block2 is 185N, I thought that would be the only force acting on Block1, science it is frictionless. And they would have the same accelration since they are connected so i set up an equation like this Fx=185=m1a = a=4.3m/s^2. But this is wrong, and I know i set it up wrong.......
"In the drawing, the weight of the block on the table(block1) is 422N and that of the hanging block(block2) is 185N. Ignoring all frictional effects and assuming the pulley to be massless, find (a) the acceleration of the two blocks and (b) the tension in the cord."
o-----------Block1
I
I
I
Block2
(excuse my poor excuse for trying to draw with letters)
What I did was since we know that block2 is 185N, I thought that would be the only force acting on Block1, science it is frictionless. And they would have the same accelration since they are connected so i set up an equation like this Fx=185=m1a = a=4.3m/s^2. But this is wrong, and I know i set it up wrong.......