- #1
jle1092
- 13
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A .5 kg ball is thrown vertically upward with an initial speed of 8 m/s. If the initial potential energy is taken as zero, find the following:
1. potential energy of the ball at a height of 2 m above the initial position
2. the initial kinetic energy of the ball
3. the total mechanical energy at the maximum height
PE= mgy
Potential Energy=(mass)(Gravity)(height)
KE(initial)+PE(initial)=KE(final)+PE(final)
1. So for the first one, this is how I solved for the potential energy:
PE=mgy
PE=(.5kg)(9.8m/s^2)(2m)
PE=9.8 J
I am pretty confident with how I solved this part of the problem.
2. The second question I had a little more trouble with.
I used:
KE(initial)+PE(initial)=KE(final)+PE(final), and plugged in what I knew:
KE(inital) + 0=0 + PE(final)
So since KE=PE I said that KE would also equal 9.8 J.
3. So if the ball had 9.8 J to begin with, and ended with 9.8 J, shouldn't this answer also be 9.8 J?
Thanks for the help.
1. potential energy of the ball at a height of 2 m above the initial position
2. the initial kinetic energy of the ball
3. the total mechanical energy at the maximum height
PE= mgy
Potential Energy=(mass)(Gravity)(height)
KE(initial)+PE(initial)=KE(final)+PE(final)
1. So for the first one, this is how I solved for the potential energy:
PE=mgy
PE=(.5kg)(9.8m/s^2)(2m)
PE=9.8 J
I am pretty confident with how I solved this part of the problem.
2. The second question I had a little more trouble with.
I used:
KE(initial)+PE(initial)=KE(final)+PE(final), and plugged in what I knew:
KE(inital) + 0=0 + PE(final)
So since KE=PE I said that KE would also equal 9.8 J.
3. So if the ball had 9.8 J to begin with, and ended with 9.8 J, shouldn't this answer also be 9.8 J?
Thanks for the help.