- Thread starter
- Admin
- #1

Here is a link to the question:Calculus 1 Help on Mean Value Theorem?

I don't know how to do this.

Consider the function f(x)=7-8x^2 on the interval [-3,6]. Find the average or mean slope of the function on this interval, i.e. ((f(6)-f(-3))/(6-(-3)))=

By the Mean Value Theorem, we know there exists a c in the open interval (-3,6) such that f'(c) is equal to this mean slope. For this problem, there is only one c that works. Find it.

If someone could help, that would be great! Thanks!

Calculus 1 Help on Mean Value Theorem? - Yahoo! Answers

I have posted a link there to this topic so the OP can find my response.