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You might need to tidy that up a bit. And check you aren't missing some brackets.mustafamistik said:
What does that tell you about the acceleration of ##m_1##?
You might need to tidy that up a bit. And check you aren't missing some brackets.mustafamistik said:Using ##F=m*a##;
##M*g-(m_1+m_2)*sin(16)*g/(M+m_1+m_2)=a##
You are right.PeroK said:You might need to tidy that up a bit. And check you aren't missing some brackets.
What does that tell you about the acceleration of ##m_1##?
And there's an upper limit on ##a##, correct? Depending on ##\mu##?mustafamistik said:You are right.
##(M*g-(m_1+m_2)*sin(16)*g)/(M+m_1+m_2)=a##
=> ##(g*(M-(m_1+m_2)*sin(16)))##
a is acceleration of the all system.
This is the point where I stuck.PeroK said:And there's an upper limit on ##a##, correct? Depending on ##\mu##?
I don't know what you mean. You did that already:mustafamistik said:This is the point where I stuck.
mustafamistik said:This equation to find maximum acceleration. (m2*g*cos(16)* μ) -(m2*g*sin(16))=m2*a (F=ma)
Is that equation true ?PeroK said:I don't know what you mean. You did that already:
Maybe it was so long ago!
I think so. You just have to put everything together now.mustafamistik said:Is that equation true ?
Thank you and @haruspex for helping solve and understand this question. Also thanks for your interest.PeroK said:I think so. You just have to put everything together now.