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- Apr 13, 2013

- 3,718

[tex]\left | x_{k}-x_{k-1} \right | [/tex] < ε and [tex] \left | f(x_{k}) \right | [/tex] < ε

are valid. )

At the bisection method I found the maximum number of iterations needed so that the method converges,using the formula [tex] n=log_{2}(\frac{b-a}{ε}) [/tex] (or am I wrong? ).Is there a similar formula to find the maximum number of iterations needed so that the Newton method converges?