Net force on 'ground' with object on top of it....?

In summary, the conversation discusses the forces acting on a stationary object resting on the ground, including the weight force and normal reaction force. It also mentions the normal force of the ground preventing a net force downwards and the increasing pressure and spherical shape of planets due to gravity. The conversation concludes with a question about the normal reaction force at the center of the Earth.
  • #1
orthogonal1
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A stationary object resting upon the ground experiences two forces, the weight force as well as the normal reaction force of the ground. These forces sum to zero. The ground however experiences the weight force acting downwards upon it. What other force acts upon the ground to prevent it from experience a net force downwards? Is it the normal force of the ground immediate below? If we continue this until we get to the centre of the earth, what is the normal reaction force of an infinitesimally thin piece of ground immediately about the centre of the Earth?
 
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  • #2
orthogonal1 said:
A stationary object resting upon the ground experiences two forces, the weight force as well as the normal reaction force of the ground. These forces sum to zero. The ground however experiences the weight force acting downwards upon it. What other force acts upon the ground to prevent it from experience a net force downwards? Is it the normal force of the ground immediate below? If we continue this until we get to the centre of the earth, what is the normal reaction force of an infinitesimally thin piece of ground immediately about the centre of the Earth?
What is the normal force on the hub of a bicycle wheel from all of the spokes? What is it about the bicycle wheel that allows such a force to exist? Is there a similar effect that you are not accounting for within the Earth?
 
  • #3
Good reasoning. And it leads to something strange, so there must be a flaw somewhere. Because if you come from the other side of the Earth the forces are pointing the other way!
One of the flaws makes things worse: the further down you go, the smaller the area of the remaining sphere that has to deliver all this normal force ! So would that force become bigger and bigger, to even go to infinity at the very center ?

Gravity makes things with mass attract each other. But things have volume, so at some point the opposite force (opposition to compression) prevents further clumping together and disappearing into a zero volume.

As they say: under pressure everything becomes fluid. That's the reason planets are spherical. If they were cubic, the corner tips would ecxercise so much pressure on the material underneath that the latter would give way until things even out.
 
  • #4
orthogonal1 said:
What other force acts upon the ground to prevent it from experience a net force downwards? Is it the normal force of the ground immediate below?
Yep.
If we continue this until we get to the centre of the earth, what is the normal reaction force of an infinitesimally thin piece of ground immediately about the centre of the Earth?
Keep going! The line of logic you are on is working fine.
 
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Related to Net force on 'ground' with object on top of it....?

What is net force?

Net force is the overall force acting on an object, taking into account all the individual forces acting on it.

Why is it important to consider net force?

Considering net force is important because it determines the overall motion of an object. If the net force is zero, the object will remain at rest or continue moving at a constant velocity. If the net force is not zero, the object will accelerate in the direction of the net force.

How is net force calculated?

Net force is calculated by adding up all the individual forces acting on an object. Forces can be added together if they act in the same direction, and subtracted if they act in opposite directions. The resulting sum is the net force.

What factors affect the net force on an object?

The net force on an object is affected by the magnitude and direction of the individual forces acting on it. It is also affected by the mass of the object, as greater mass requires greater force to cause the same acceleration.

How does the presence of an object on top of the ground affect the net force on the ground?

The presence of an object on top of the ground does not affect the net force on the ground itself. However, the weight of the object will exert a force on the ground, causing it to experience a net force in the opposite direction. This is known as Newton's third law of motion.

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