- #1
James Brady
- 105
- 4
I'm working with the Nernst equation with pressure differences right now:
## E = E_t + \frac{RT}{nF}ln ((P/P_0)^{\Delta \eta_G})##
I'm assuming pure reactants here so, so I'm omitting the product terms: ##\frac{\Pi_{products} x_i ^{\nu_i}}{\Pi_{reactants} x_i ^{\nu_i}}## which would normally also go in the logarithm.
according to my solutions manual:
##\Delta \eta_G = \nu_P - \nu_R##
##\Delta \eta_G## is referred to as "the change in the number of moles" and it looks like the value should be -1.5. However, I'm not sure how they would get that from the stoichiometry of the hydrogen-oxygen reaction:
##H_2 + \frac{1}{2}O_2 = H_2 O##
##1 H_2 O - (1 H_2 + \frac{1}{2}O_2) = -0.5 ## less moles overall. I'm not sure how they got -1.5. I'm not sure what "nu" is for products and reactants and it's real meaning.
## E = E_t + \frac{RT}{nF}ln ((P/P_0)^{\Delta \eta_G})##
I'm assuming pure reactants here so, so I'm omitting the product terms: ##\frac{\Pi_{products} x_i ^{\nu_i}}{\Pi_{reactants} x_i ^{\nu_i}}## which would normally also go in the logarithm.
according to my solutions manual:
##\Delta \eta_G = \nu_P - \nu_R##
##\Delta \eta_G## is referred to as "the change in the number of moles" and it looks like the value should be -1.5. However, I'm not sure how they would get that from the stoichiometry of the hydrogen-oxygen reaction:
##H_2 + \frac{1}{2}O_2 = H_2 O##
##1 H_2 O - (1 H_2 + \frac{1}{2}O_2) = -0.5 ## less moles overall. I'm not sure how they got -1.5. I'm not sure what "nu" is for products and reactants and it's real meaning.