- Thread starter
- #1

- Thread starter charki126
- Start date

- Thread starter
- #1

- Mar 1, 2012

- 655

Guessing at your syntax ... are the following interpretations correct?

$y = A\sin\left[\dfrac{2\pi}{\lambda} \cdot (x + \alpha)\right]$

$z = A\sin\left(\dfrac{2\pi}{\lambda} \cdot x \right)$

If so, then the period of both sinusoids is $\lambda$, hence I agree that the two will be in phase for $\alpha = k \lambda \, , \, k \in \mathbb{Z}$

$y = A\sin\left[\dfrac{2\pi}{\lambda} \cdot (x + \alpha)\right]$

$z = A\sin\left(\dfrac{2\pi}{\lambda} \cdot x \right)$

If so, then the period of both sinusoids is $\lambda$, hence I agree that the two will be in phase for $\alpha = k \lambda \, , \, k \in \mathbb{Z}$

Last edited: