Need help with later magnification and location

In summary, two lenses with focal lengths of +20 m and +30 m are placed on the axis with an object fixed 50 m to the left of lens 1. The lateral location of the final image relative to lens 2 is found to be 3 m for the case = 30.0. This agrees with the equation for the effective focal length of two lenses in contact, showing the accuracy of the result.
  • #1
dkgrubby
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Need help with later magnification and location!

Two lenses, with = +20.0 and = +30.0 , are placed on the axis, as shown in the figure. An object is fixed 50.0 to the left of lens 1, and lens 2 is a variable distance to the right of lens 1.

Part A
Find the lateral location of the final image relative to lens 2 for the case = 100 .
=54.5
Correct


Part B
Find the lateral magnification of the final image relative to lens 2 for the case = 100 .
=

One attempt remaining; Try Again


Part C
Find the lateral location of the final image relative to lens 2 for the case = 30.0 .
=3.00
Correct


Part D
Find the lateral magnification of the final image relative to lens 2 for the case = 30.0 .
=

Try Again; 4 attempts remaining


Part E
Find the lateral location of the final image relative to lens 2 for the case = 0.
=


Try Again; 5 attempts remaining


Part F
Find the lateral magnification of the final image relative to lens 2 for the case = 0.
=



Part G
Show that your result for part E agrees with the relation for the effective focal length of two lenses in contact, .
Essay answers are limited to about 500 words (3800 characters maximum, including spaces).
 
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  • #2
When two lenses of focal lengths f1 and f2 are in contact, the effective focal length is given by the equation: f = (f1f2)/(f1+f2). In this case, f1=20 m and f2=30 m, so the effective focal length is f = (20*30)/(20+30) = 12 m. The lateral location of the final image relative to lens 2 can be found by applying the thin lens equation 1/p+1/q = 1/f, where p is the object distance, q is the image distance, and f is the focal length. Since the object is 50 m from lens 1 and the focal length is 12 m, q = -12 m. This means that the lateral location of the final image relative to lens 2 is 3 m, which agrees with the result obtained in Part E. Therefore, this shows that the result for part E agrees with the relation for the effective focal length of two lenses in contact.
 

Related to Need help with later magnification and location

What is later magnification?

Later magnification refers to the increase in image size that occurs when an image is viewed through a magnifying lens or device.

Why is later magnification important?

Later magnification allows scientists to view objects that are too small to be seen with the naked eye, allowing for more detailed examination and analysis.

How is later magnification achieved?

Later magnification can be achieved through the use of lenses, microscopes, or other devices that increase the size of an image by bending light or using other magnifying techniques.

What are the limitations of later magnification?

The limitations of later magnification include distortion of the image, decreased resolution, and the possibility of introducing artifacts into the image.

What is the relationship between later magnification and location?

The relationship between later magnification and location is that the magnification of an image can vary depending on the distance between the object and the lens or device used to view it. Additionally, the location of the object itself can affect the ability to magnify and view it clearly.

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