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MissP.25_5
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Can someone help me solve this? I don't really understand how to do this.
A 1kvA reactor's capacity is needed to be enlargedto 81kvA. How much does its dimension needs to be multiplied?
Hint:
when its dimension is m times enlargened, surface A'=m'A, flux ∅'=m^2∅, current I'=m^2I, voltage E'=m^2E, Capacity E'I'=m^4EI.
Loss Pe'=m^3Pe
Temperature θ'=loss/surface area = (m^3Pe)/m^2A = mθ
My attempt:
Capacity E'I'=m^4EI. So,
E'I' / EI = m^4
81/1 = m^4
m = 3.
Is the answer 3?
A 1kvA reactor's capacity is needed to be enlargedto 81kvA. How much does its dimension needs to be multiplied?
Hint:
when its dimension is m times enlargened, surface A'=m'A, flux ∅'=m^2∅, current I'=m^2I, voltage E'=m^2E, Capacity E'I'=m^4EI.
Loss Pe'=m^3Pe
Temperature θ'=loss/surface area = (m^3Pe)/m^2A = mθ
My attempt:
Capacity E'I'=m^4EI. So,
E'I' / EI = m^4
81/1 = m^4
m = 3.
Is the answer 3?
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