n^lnx = x simple question

[tmt]

Hi,

I learned today that n^lx = x

Is this where n is a variable a a fixed constant?

Thanks ,

Tim

 

[MarkFL]

The actual identity is:

\(\displaystyle a^{\log_a(x)}=x\)

For suitable values of $a$, usually taken to be a positive fixed value not equal to 1.

 

[mente oscura]

Hi,

I learned today that n^lx = x

Is this where n is a variable a a fixed constant?

Thanks ,

Tim

Hello.

But, yes, it is constant:

[tex]\log_e(x) \ \log_e(n)=\log_e(x) \rightarrow{}n=e[/tex]

It is correct, isn't it?

Regards.