- #1
wachaif
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Response to:
force question
i don't understand this..the way the forces go
if someone could show me how to do it and the steps..that would be great:
The static friction coefficient btw a wall and a pic is 0.7 while the kinetic one is 0.3. By what force shoudl one push the 6kg pic against the wall so that it will not slide?What if he/she pushed the pic with a force making an angle of 30 degrees to the horizontal (both cases)
1. Break the F into x-y component such as x=Fcos30 ,y = Fsin30
2.Since friction= U times normal force .and the normal force =Fcos 30
3.Set f=mg+Fsin30
U(Fcos30)=6(9.8) + F sin 30
0.7(Fcos30)=6(9.8) + F sin 30
F=553.58N
Am I correct ?
force question
i don't understand this..the way the forces go
if someone could show me how to do it and the steps..that would be great:
The static friction coefficient btw a wall and a pic is 0.7 while the kinetic one is 0.3. By what force shoudl one push the 6kg pic against the wall so that it will not slide?What if he/she pushed the pic with a force making an angle of 30 degrees to the horizontal (both cases)
1. Break the F into x-y component such as x=Fcos30 ,y = Fsin30
2.Since friction= U times normal force .and the normal force =Fcos 30
3.Set f=mg+Fsin30
U(Fcos30)=6(9.8) + F sin 30
0.7(Fcos30)=6(9.8) + F sin 30
F=553.58N
Am I correct ?
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