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#### Petrus

##### Well-known member

- Feb 21, 2013

- 739

\(\displaystyle f(x,y)=x^5y^4e^{-3x-3y}\)

In the triangle has vertices in points \(\displaystyle \left(0,0 \right)\),\(\displaystyle \left(6,0 \right)\) and \(\displaystyle \left(0,6 \right)\)

Before I start I want to warn that I used google translate in the text 'In the triangle has vertices in points'

Progress:

I start to derivate (I need confirm if I did right when I did it)

Derivate x: \(\displaystyle 5x^4y^4e^{-3x-3y}(-3-3y)\)

Derivate y: \(\displaystyle x^5 4y^3e^{-3x-3y}(-3x-3)\)