Momentum transfer perpendicular to velocity of proton?

In summary, the Bethe equation assumes that the momentum transfer is perpendicular to the direction of the particle. In Allison & Cobb (1980), it is stated that the first two terms of the Photoabsorption Ionization model are due to the magnetic vector potential in the Coulomb gauge, where the electric field is transverse to the direction of 3-momentum transfer. This is justified by the fact that the magnetic vector potential A is in units of momentum per charge, excluding any hard collisions. For further clarification, refer to the link provided by ORF.
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rjseen
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An assumption in deducing the Bethe equation is that the momentum transfer is perpendicular to the direction of the particle.

ALSO

In Allison & Cobb (1980), just after eq. 28, they state that the first two terms of the Photoabsorption Ionization model arise from the magnetic vector potential in the Coulomb gauge, for which the electric field is transverse to the direction of 3-momentum transfer.

I know that the magnetic vector potential A is in units of momentum per charge, so ignoring hard collisions, how does the justification of this look?
 
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Related to Momentum transfer perpendicular to velocity of proton?

1. What is momentum transfer perpendicular to velocity of proton?

Momentum transfer perpendicular to velocity of proton refers to the change in momentum that occurs when a proton changes direction without changing its speed. This is known as the perpendicular component of momentum transfer because it is perpendicular to the proton's original velocity.

2. How is momentum transfer perpendicular to velocity of proton calculated?

The magnitude of momentum transfer perpendicular to velocity of proton can be calculated using the formula p = mv, where p is the momentum, m is the mass of the proton, and v is its velocity. The direction of the momentum transfer can be determined using vector analysis techniques.

3. What factors affect the magnitude of momentum transfer perpendicular to velocity of proton?

The magnitude of the momentum transfer is affected by the mass and velocity of the proton, as well as the angle at which the change in direction occurs. A larger mass or higher velocity will result in a greater momentum transfer, while a smaller angle will result in a smaller perpendicular component of momentum transfer.

4. What is the significance of momentum transfer perpendicular to velocity of proton?

Momentum transfer perpendicular to velocity of proton is an important concept in understanding the motion of charged particles in electromagnetic fields. It helps to explain how particles can change direction without changing their speed, and is crucial in fields such as particle physics and plasma physics.

5. How does momentum transfer perpendicular to velocity of proton relate to other physical quantities?

Momentum transfer perpendicular to velocity of proton is closely related to other physical quantities such as force, acceleration, and energy. It can also be used to calculate the radius of curvature of a charged particle's path in a magnetic field. Understanding this concept is essential in many areas of physics and engineering.

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