Minimum Thickness of Dielectric

IN VALUE OF E = \frac{p}{t}. b) What is the capacitance per unit length of the resulting arrangement.The capacitance per unit length is given by C = \frac{Q}{V} = \frac{Q}{E/p} = \frac{Q}{(Q/L)*(1/2*pi*e*p)/p} = \frac{2*pi*e*L}{ln(b/a)} where L is the length of the cable.
  • #1
iblackford
1
0
1. Basically, we have coaxial cable with an inner wire of radius a,
perfectly conducting, straight and infinitely long, with radius a, surrounded by an outer hollow cylinder, also made
from perfectly conducting material, having inner radius b and outer radius c. The hollow cylinder functions as a
return wire, and is coaxial with the inner wire. If the space between the wires is air or vacuum, the electric field
between the inner and return wires is shown to be

E = (Q/L)*(1/2*pi*e*p)

where Q/L is the charge per unit length and  the cylindrical distance between the wires.
Suppose the ~E field cannot be allowed to reach values above the value it reaches in the middle of the arrangement,
where p = (a+b)/2
2 . This can be achieved by shielding the inner cable with a dielectric of permittivity e.
a) What is the minimum value of e and the minimum thickness of dielectric coating that will ensure that the field
is everywhere below its maximal value?
b) What is the capacitance per unit length of the resulting arrangement.

I'm not sure how to do the first part of the problem, I think I would sub in my p = a+b/2 into my first equation, but I'm not sure what to do from there. Any help would be highly appreciated.
 
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  • #2
iblackford said:
1. Basically, we have coaxial cable with an inner wire of radius a,
perfectly conducting, straight and infinitely long, with radius a, surrounded by an outer hollow cylinder, also made
from perfectly conducting material, having inner radius b and outer radius c. The hollow cylinder functions as a
return wire, and is coaxial with the inner wire. If the space between the wires is air or vacuum, the electric field
between the inner and return wires is shown to be
E = (Q/L)*(1/2*pi*e*p)
where Q/L is the charge per unit length and p the cylindrical distance between the wires.
Just use Gauss' law for a Gaussian cylinder of radius p:
[tex]\int E\cdot dA = \frac{q}{\epsilon_0}[/tex]
Suppose the ~E field cannot be allowed to reach values above the value it reaches in the middle of the arrangement,
where p = (a+b)/2
2 . This can be achieved by shielding the inner cable with a dielectric of permittivity e.
a) What is the minimum value of e and the minimum thickness of dielectric coating that will ensure that the field
is everywhere below its maximal value?
The maximum field is the E determined in 1 where p = (a+b)/2. A dielectric of thickness t will reduce this by a factor [itex]\frac{1}{\epsilon}[/itex]

from p=a to p = a+t. So work out the expression for E at p=a+t. The value of E from p=a+t decreases as 1/p.

AM
 
Last edited:

Related to Minimum Thickness of Dielectric

What is the minimum thickness of dielectric?

The minimum thickness of dielectric refers to the smallest possible distance between two conducting plates in a capacitor that still allows for the separation of electric charges and the storage of electrical energy.

Why is the minimum thickness of dielectric important?

The minimum thickness of dielectric is important because it determines the capacitance, or ability to store electric charge, of a capacitor. It also affects the breakdown voltage, or the maximum voltage that the capacitor can withstand before losing its insulating properties.

How is the minimum thickness of dielectric calculated?

The minimum thickness of dielectric is calculated using the formula t = (k * ε0 * A) / C, where t is the thickness of the dielectric, k is the dielectric constant, ε0 is the permittivity of free space, A is the area of the capacitor plates, and C is the desired capacitance.

What factors affect the minimum thickness of dielectric?

The factors that affect the minimum thickness of dielectric include the dielectric constant, the permittivity of free space, the area of the capacitor plates, and the desired capacitance. Other factors such as temperature and material properties of the dielectric can also play a role.

How does the minimum thickness of dielectric impact the performance of a capacitor?

The minimum thickness of dielectric directly affects the capacitance and breakdown voltage of a capacitor, which in turn affects its ability to store and discharge electric charge. A thinner dielectric can result in a higher capacitance and lower breakdown voltage, while a thicker dielectric can result in a lower capacitance and higher breakdown voltage.

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