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p671
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Homework Statement
Homework Equations
F = ma; f = µN
The Attempt at a Solution
Let F' be the action-reaction force between box m and box M
f be the friction on small box m
For small box m:
F' = ma
f - mg = 0
µF' - mg = 0 since f = µF'
µma - mg = 0 since F' = ma
a = g / µ = 9.81 m/s2 / 0.2 = 49.05 m/s2
which is not equal to the given acceleration of 2.0 m/s2
Please help. Thanks
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