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Shah 72
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I don't understand how to find the distance that robot travels in 10s.
Thank you very much!skeeter said:t=0 to t=2 … the robot moves away from its starting position 2.56m
t=2 to t=5 … the robot moves back toward its starting position 0.81m
t=5 to t=8 … the robot moves away again from its starting position 0.81m
t=8 to t=10 … the robot moves back to its starting position 2.56m
total distance traveled by the robot would be … ?
Distance refers to the total length traveled by an object, while displacement refers to the straight-line distance between the starting and ending points of an object's motion. Displacement takes into account both the distance and direction of an object's motion.
The equation for average velocity is displacement divided by time, or v = Δx / Δt. This equation calculates the average speed and direction of an object's motion over a specific period of time.
Acceleration is the rate of change of an object's velocity. If an object is accelerating, it is changing its speed and/or direction. A positive acceleration means the object is speeding up, while a negative acceleration means the object is slowing down.
Yes, an object can have a constant speed but changing velocity. This can occur when an object is moving in a circular path, as its velocity is constantly changing due to the change in direction, but its speed remains constant.
The slope of a position-time graph represents an object's velocity. A steeper slope indicates a higher velocity, while a flatter slope indicates a lower velocity. A horizontal line on a position-time graph represents an object at rest, with a velocity of 0.