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For the first part before the rope is detached

I calculated

R=40cos 18+8sin 10

Coefficient of friction =0.514

F=m×a

So I got a = 0.003m/s^2.

I then calculated s= ut +1/2 at^2 and got s1 =0.0135m.

I calculated v=0.009m/s

Part 2 when the rope is detached

R=40cos 18

By using F=m×a

I got a=0.714m/s^2.

Iam not getting the right ans for the total distance.

The ans in the textbook is 18.5m.

Pls help