- Thread starter
- #1

So I did F=m×a

-0.4×50cos25- 50sin25= 5a

a=-7.85m/s^2.

I don't know how to calculate after this. Pls help

- Thread starter Shah 72
- Start date

- Thread starter
- #1

So I did F=m×a

-0.4×50cos25- 50sin25= 5a

a=-7.85m/s^2.

I don't know how to calculate after this. Pls help

- Mar 1, 2012

- 935

initial velocity > 0, acceleration < 0

$a = -g(\sin{\theta} + \mu\cos{\theta})$

$\Delta x = \dfrac{0^2-12^2}{2a} = 9.17 \, m$

let downhill be positive …

initial velocity = 0, final velocity > 0, acceleration > 0, delta x > 0

$a = g(\sin{\theta} - \mu \cos{\theta})$

$v_f = \sqrt{ 0^2 + 2a \Delta x}$

- Thread starter
- #3

Thank you so much!!!

initial velocity > 0, acceleration < 0

$a = -g(\sin{\theta} + \mu\cos{\theta})$

$\Delta x = \dfrac{0^2-12^2}{2a} = 9.17 \, m$

let downhill be positive …

initial velocity = 0, final velocity > 0, acceleration > 0, delta x > 0

$a = g(\sin{\theta} - \mu \cos{\theta})$

$v_f = \sqrt{ 0^2 + 2a \Delta x}$