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- #1

R=2000cos6= 1989N

F=1000-(0.4×1989+2000sin6),

By using F=m×a, I get a=-0.023m/s^2

V^2=u^2+2as, u=2m/s, s=10m, I get v=1.88m/s.

Now for u=1.88 and v=1.5 and using the same v^2= u^2+2as, I get s=27.9. So total distance will be 37.9. But the textbook ans is 37.4m. Pls advise if my ans is correct