- #1
jay
- 7
- 0
Hai all,
In projectiles the horizondal component of their velocity remains constant and veritical compont changes as it gets accelarated.So with this, I think we can find an experiment that gives the accelaration due to gravity(g) without a clock.i.e if we are droping a ball from a table of height 5m with some horizondal velocity(its veritical component will be zero initialy)it reaches a horizondal distance of 10m at the bottom from the table.If we repeate this experiment with a table of height 10m and with same ball and same horizondal velocity the horizondal distance traveled is 13m.Then i don't know is there any way to calculate the accelaration due to gravity at that place.Any way it is clear that ball travels its second 5m (vertical) faster in its 10m drop.
Anyway if a clock is a must for calculating 'g' please say why?
**These values are not correct...
Jay..
In projectiles the horizondal component of their velocity remains constant and veritical compont changes as it gets accelarated.So with this, I think we can find an experiment that gives the accelaration due to gravity(g) without a clock.i.e if we are droping a ball from a table of height 5m with some horizondal velocity(its veritical component will be zero initialy)it reaches a horizondal distance of 10m at the bottom from the table.If we repeate this experiment with a table of height 10m and with same ball and same horizondal velocity the horizondal distance traveled is 13m.Then i don't know is there any way to calculate the accelaration due to gravity at that place.Any way it is clear that ball travels its second 5m (vertical) faster in its 10m drop.
Anyway if a clock is a must for calculating 'g' please say why?
**These values are not correct...
Jay..