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Physics Mechanics- connected particles

Shah 72

Member
Apr 14, 2021
193
A passenger lift had mass 500 kg. The breaking tension of the cable is 12000N. The max acceleration of the lift is 0.75 m/s^2
a) if the lift travels at its max acceleration, calculate the max mass of the passengers:
1)when the lift is accelerating upwards
2) when the lift is accelerating downwards
b) taking the average mass of a person to be 75 kg, what is the max number of passengers that should be allowed to travel in the lift?
 

skeeter

Well-known member
MHB Math Helper
Mar 1, 2012
935
A passenger lift had mass 500 kg. The breaking tension of the cable is 12000N. The max acceleration of the lift is 0.75 m/s^2
a) if the lift travels at its max acceleration, calculate the max mass of the passengers:
1)when the lift is accelerating upwards
2) when the lift is accelerating downwards
b) taking the average mass of a person to be 75 kg, what is the max number of passengers that should be allowed to travel in the lift?
What have you accomplished with this one?
 

Shah 72

Member
Apr 14, 2021
193
What have you accomplished with this one?
So it should be T- mass of lift× g- mass of passengers ×g= ( M+m) ×a
Iam not getting the right ans that is mentioned in the textbook
 

Shah 72

Member
Apr 14, 2021
193

skeeter

Well-known member
MHB Math Helper
Mar 1, 2012
935
Are you going to share your solution so others may benefit?

That’s a big part of being a member of MHB. Get some help … give some help.
 

Shah 72

Member
Apr 14, 2021
193
Are you going to share your solution so others may benefit?

That’s a big part of being a member of MHB. Get some help … give some help.
Ofcourse.
So I did T- Mg-mg=(M+m)×a
I got M=616kg
b) T- Mg-mg= -(M+m)×a
m=797 kg
2) I did 616/75= 8 people