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I have an equation which looks like quadratic to me.

2(x - 5)

^{2 }= 32

Can I divide both sides by 2?

(x - 5)

^{2}= 16

Can I take the square root?

x - 5 = + or - 4

if x = 5 plus 4 = 9

if x = 5 - 4 = 1

Therefore my roots would be;

x = 9 or x = 1

Is this method acceptable and the correct way to find the values of x. I know it works out OK but am wondering about the way I have done it?

Thanks