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warfreak131
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Homework Statement
The figure (attached image) shows a pulse on a string of length 100m with fixed ends. The pulse is traveling to the right without any change of shape, at a speed of 40 m/s.
What is the maximum transverse velocity of the string?
Homework Equations
y = A Sin(kx-wt)
The Attempt at a Solution
I said that the wave had a length of 2 meters. That makes the wave number 2pi/2 = pi. And since we know the velocity and wavelength, we can find the frequency, and therefore, the angular frequency. 40(m/s)/2m = 20 hz. w=2 pi f = 2 pi 20 = 40 pi. And the amplitude is .1 m.
This makes the equation y = .1 Sin(pi x - 40 pi t)
The velocity is the derivative of position, giving us -12.5 Cos[40 pi t - pi x].
Therefore, the maximum velocity would be when the derivative of velocity = 0.
y''=a= 1580 Sin[40 pi t - pi x].
I get that y'' = 0 when either x=40t or t=x/40. If I plug this into y', I get the argument in the cosine to equal 0, which makes cosine equal 1. This would just leave the constant term as the answer, making it (a magnitude of) 12.5 m/s. But according to the book, the answer is 4 m/s. How did they get this?
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