Maximum speed of a box compressing a spring on an inclined p

In summary, the box slides down a frictionless ramp at an angle theta and after sliding a distance d it strikes a spring of force constant k. The box compresses the spring momentarily stops and then begins to slide back up the ramp. The maximum speed of the box is v = 1.96m/s.
  • #1
harik2000
3
0

Homework Statement



A box of mass m = 40kg is released from rest at thte top of a frictionless ramp. The ramp makes an angle theta = 45 degrees to the horizontal. After sliding fom the rigin a distance d = 2.00 m down the ramp, the box strikes a spring of force constant k = 500 N/m. The box compresses the spring momentarily stops, and then begins to slide back up the ramp. What is the maximum speed of the box?

Homework Equations

The Attempt at a Solution


mgsin(45) = kx
(9.81 * 40)sin45 = 500x
x= 0.5547

1/2(k)(x^2) = 1/2(m)(v^2)
v = 1.96m/s

Can anyone verify this pls?
 
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  • #2
harik2000 said:
mgsin(45) = kx
(9.81 * 40)sin45 = 500x
x= 0.5547

1/2(k)(x^2) = 1/2(m)(v^2)
v = 1.96m/s

Can anyone verify this pls?

It doesn't look right to me. Any reason why you used force considerations to do the first part, and energy do do the latter part?
 
  • #3
Mister T said:
It doesn't look right to me. Any reason why you used force considerations to do the first part, and energy do do the latter part?

I was trying to find the displacement provided when the ball compresses the spring the most however realized that I did not use potential energy mgh and I was confused. Can you show me the steps? I am confused.
 
  • #4
harik2000 said:
I was trying to find the displacement provided when the ball compresses the spring the most however realized that I did not use potential energy mgh and I was confused. Can you show me the steps? I am confused.

What part confuses you?
 
  • #5
I am confused about the potential energy so it would be equal to mgh = 1/2 k x^2 but how would that help solve for v?
 
  • #6
harik2000 said:
I am confused about the potential energy so it would be equal to mgh = 1/2 k x^2 but how would that help solve for v?

Solve it for x and tell us what you get.
 
  • #7
harik2000 said:
I am confused about the potential energy so it would be equal to mgh = 1/2 k x^2 but how would that help solve for v?
It won't.
First, please check you have stated the problem exactly.
Is it the whole problem or are there more parts? If there are more parts (and even if there aren't) consider the possibility that not all the information is relevant to finding the max speed.
Then consider at what point in the whole process you would expect max speed to be reached.
 

1. What is the maximum speed that a box can reach while compressing a spring on an inclined plane?

The maximum speed of a box compressing a spring on an inclined plane depends on factors such as the mass of the box, the angle of the incline, and the spring constant. It can be calculated using the equation v = √(2mg(sinθ - μcosθ)/k), where v is the maximum speed, m is the mass of the box, g is the acceleration due to gravity, θ is the angle of the incline, μ is the coefficient of friction, and k is the spring constant.

2. How does the angle of the incline affect the maximum speed of the box?

The angle of the incline has a direct impact on the maximum speed of the box. As the angle increases, the maximum speed decreases. This is because a steeper incline means a greater force is acting against the box, slowing it down. Additionally, a higher angle can also increase the coefficient of friction, further reducing the maximum speed.

3. Can the maximum speed of the box be greater than the speed of sound?

No, the maximum speed of the box compressing a spring on an inclined plane cannot exceed the speed of sound. The speed of sound is a physical limit and cannot be surpassed by an object with mass.

4. How does the mass of the box affect the maximum speed?

The mass of the box has a direct impact on the maximum speed. As the mass increases, the maximum speed decreases. This is because a heavier box requires more force to move it up the incline, resulting in a lower maximum speed.

5. Can the spring constant affect the maximum speed of the box on an inclined plane?

Yes, the spring constant can affect the maximum speed of the box on an inclined plane. A higher spring constant means a stiffer spring, which will require more force to compress. This can result in a lower maximum speed for the box. Additionally, a lower spring constant can also result in a lower maximum speed as the spring may not provide enough force to propel the box up the incline.

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