- Thread starter
- #1

$$

\frac{df}{dN_t} =0\Rightarrow N_m

$$

Then $N_{\text{max}} = f(N_m)$, correct?

Because whenever I try to solve

$$

N_{t+1} =\frac{(1+r)N_t}{1+rN_t}

$$

It doesn't work.

The derivative is

$$

\frac{1+r}{(1+rN_t)^2}=0

$$

- Thread starter dwsmith
- Start date

- Thread starter
- #1

$$

\frac{df}{dN_t} =0\Rightarrow N_m

$$

Then $N_{\text{max}} = f(N_m)$, correct?

Because whenever I try to solve

$$

N_{t+1} =\frac{(1+r)N_t}{1+rN_t}

$$

It doesn't work.

The derivative is

$$

\frac{1+r}{(1+rN_t)^2}=0

$$