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#### Funfinder15

##### New member

- Jan 12, 2020

- 1

- Thread starter Funfinder15
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- Thread starter
- #1

- Jan 12, 2020

- 1

- Mar 1, 2012

- 980

$\begin{bmatrix}

-5t & 6\\

t & -t

\end{bmatrix}

\cdot

\begin{bmatrix}

t & 6\\

t & 5t

\end{bmatrix}=

\begin{bmatrix}

1 & 0\\

0 & 1

\end{bmatrix}$

Multiply $[M]^{-1} \cdot [M]$ , then set each corresponding element in the product equal to the elements in the identity matrix to get the desired equation in $t$.

Give it a go and see how you do ...